2011
DOI: 10.4171/ggd/135
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Grothendieck’s problem for 3-manifold groups

Abstract: Abstract. The following problem was posed by Grothendieck:Let u W H

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Cited by 20 publications
(18 citation statements)
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“…There are many classes of groups Γ that can never have a subgroup P for which (Γ, P ) is a Grothendieck Pair; as in [40], we call such groups Grothendieck Rigid.…”
Section: 2mentioning
confidence: 99%
See 1 more Smart Citation
“…There are many classes of groups Γ that can never have a subgroup P for which (Γ, P ) is a Grothendieck Pair; as in [40], we call such groups Grothendieck Rigid.…”
Section: 2mentioning
confidence: 99%
“…For those modelled on SOL geometry, separability of subgroups can be established directly and the result follows. ⊔ ⊓ Remark: The case of finite co-volume Kleinian groups was proved in [40] without using the LERF assumption. Instead, character variety techniques were employed.…”
Section: 2mentioning
confidence: 99%
“…(A standard argument shows that two finitely generated groups have the same set of finite quotients if and only if their profinite completions are isomorphic.) Bridson, Conder and Reid have answered the corresponding question for Fuchsian groups positively [BCR14], while Long and Reid have given a positive answer to a related question [LR11]. We refer the reader to Section 8 of [Rei13] for a discussion of this and related problems.…”
mentioning
confidence: 99%
“…The number of homeomorphism classes in X T V (M ) of hyperbolic fibered 3-manifolds N with fiber of genus g ≥ 1 is finite for every M . Is this number unbounded, when M runs over the set of hyperbolic fibered 3-manifolds with fiber of given genus?The pairs of manifolds from Theorem 1.1 and Corollary 1.3 also give a negative answer to a question stated by Long and Reid in [36] (see also Remark 3.7 in [8]), as follows:Corollary 1.4. For any m ≥ 2 there exist torus bundles whose fundamental groups have isomorphic profinite completions although they are pairwise not isomorphic.…”
mentioning
confidence: 99%