“…Note that D(Σ) 2 | W = 0 since D(Σ) 2 can be presented as the locus of subschemes incident to two different sections Σ 1 , Σ 2 , and choosing these generic, this locus is disjoint from W . Hence(e c1(S) D(Σ), D(Σ)[W ]) S [2] = S [2] D(c 1 (S))D(Σ)D(Σ)[W ] = 0.Hence we find that the left hand side is equal to Q PT D(Σ), D(Σ)[W ] and can be easily computed from Theorem 8.9.Similar, with δ = c 1 (O [n] S ) we have δ[W ] = −2q 2 (Σ)v ∅ , and hence k>0 δ, δ[W ] S [2] 0,kA (−p) k = (q 2 (1), Q Hilb q 2 (Σ)) = 8(log(1 − p) − log(1 − p 2 )).…”