“…Then F implies a subgraph F of G. Since all the original vertices have degree 2 in F , they have degree 2 in F , i.e. F is a 2-factor of G. Furthermore, the cost at every original vertex is zero since c extends c. Now for any r ∈ [3,5], we have to reduce an instance (G, χ, c, k) of 2-MRCF where ∆(G) ≤ 6, d = 2, k = k min , q = 6, to an instance (G , χ , c , k ) of r-MRCF, where ∆(G ) ≤ r + 4, d = 2, k = k min , q = 7 and G is planar. Note that, since whenever G is planar, we have δ(G) ≤ 5, it does not make sense to consider other values of r.…”