2015
DOI: 10.1016/j.jpaa.2014.09.021
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Graver degrees are not polynomially bounded by true circuit degrees

Abstract: Let I A be a toric ideal. We prove that the degrees of the elements of the Graver basis of I A are not bounded above by a polynomial on the maximal true degree of the circuits of I A .

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Cited by 4 publications
(5 citation statements)
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“…We provided the positive answer for toric graph ideals only. In [8] toric graph ideals were used as counterexamples to polynomial bounds. It was able because of the pictorial description of their minimal binomials, given in [10] and [5].…”
Section: Further Remarksmentioning
confidence: 99%
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“…We provided the positive answer for toric graph ideals only. In [8] toric graph ideals were used as counterexamples to polynomial bounds. It was able because of the pictorial description of their minimal binomials, given in [10] and [5].…”
Section: Further Remarksmentioning
confidence: 99%
“…, a m ). In [9] Tatakis and Thoma disproved the conjecture and in [8] they proved that there is no polynomial bound. They provide counterexamples of toric graph ideals for which the Graver degrees are exponentialy large compared to the true circuit degrees.…”
Section: Introductionmentioning
confidence: 99%
See 1 more Smart Citation
“…Among them, the set of primitive binomials, which is known to form the Graver basis, was studied widely related to a problem initiated by Sturmfels, called true degree problem. (See [23,25,26,28] for detail.) For a toric ideal I A , an irreducible binomial B = B + − B − of I A is primitive if there exists no other binomial B 0 = B + 0 − B − 0 such that B + 0 |B + and B − 0 |B − .…”
Section: Introductionmentioning
confidence: 99%
“…Among them, the set of primitive binomials, which is known to form the Graver basis, was studied widely related to a problem initiated by Sturmfels, called true degree problem. (See [22,24,25,27] for detail.) For a toric ideal I A , an irreducible binomial B " B `´B ´of I A is primitive if there exists no other binomial B 0 " B 0 ´B0 such that B 0 |B `and B 0 |B ´.…”
Section: Introductionmentioning
confidence: 99%