2004
DOI: 10.1142/s0218216504003421
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Graphs With Disjoint Links in Every Spatial Embedding

Abstract: We exhibit a graph, G12, that in every spatial embedding has a pair of non-splittable 2 component links sharing no vertices or edges. Surprisingly, G12 does not contain two disjoint copies of graphs known to have non-splittable links in every embedding. We exhibit other graphs with this property that cannot be obtained from G12 by a finite sequence of Δ-Y and/or Y-Δ exchanges. We prove that G12 is minor minimal in the sense that every minor of it has a spatial embedding that does not contain a pair of non-spli… Show more

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Cited by 7 publications
(26 citation statements)
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“…Pair them to produce Z i . If either member of a pair has lk(Z (2) i , V 2 ) ≡ 0 mod 2, it advances to the next round. Otherwise, choose twelve paths connecting the members of each pair and produce A 1 .…”
Section: Multiple Component Constructionsmentioning
confidence: 99%
“…Pair them to produce Z i . If either member of a pair has lk(Z (2) i , V 2 ) ≡ 0 mod 2, it advances to the next round. Otherwise, choose twelve paths connecting the members of each pair and produce A 1 .…”
Section: Multiple Component Constructionsmentioning
confidence: 99%
“…Every embedding of K 3,3,2 contains a pair of disjoint 3-cycles that have non-zero linking number [1]. As these 3-cycles are disjoint, they must be of the form xa i b j and ya k b l .…”
Section: Tournaments On 8 Verticesmentioning
confidence: 99%
“…We will construct intrinsically linked tournaments with the desired score sequences by iteratively assigning orientations to the edges of K 8 in a similar manner as the proof of Proposition 3. These edges form a subgraph of K 8 that is K 3,3,2 , and thus must contain a pair of 3-cycles L 1 , L 2 with non-zero linking number [1]. If these 3-cycles are both consistently oriented, we are done.…”
Section: Tournaments On 8 Verticesmentioning
confidence: 99%
“…K 9 has an embedding with no 3-link [6], so any 9 vertex tournament has an embedding with no non-split consistently oriented 3 component link. [2] that the graph D is intrinsically linked, and in every spatial embedding, there is a pair of linked cycles C 1 , C 2 with C 1 containing the edge d 1 d 2 . We similarly expand vertex c 1 in a second copy of K 3,3,2 with the same edge orientations and denote the resulting graph D .…”
Section: Intrinsic 3-linking In Tournamentsmentioning
confidence: 99%
“…Researchers have studied variations of these properties, such as requiring every embedding of the graph to contain cycles that form a non-split n-component link [4], a non-split link where one of more of the components are non-trivial knots [5] [8], or even more complex structures [12] [2].…”
Section: Introductionmentioning
confidence: 99%