2010
DOI: 10.1016/j.disc.2010.01.003
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Generating self-complementary uniform hypergraphs

Abstract: In 2007, Szyma«ski and Wojda proved that for positive integers n, k with k ≤ n, a self-complementary k-uniform hypergraph of order n exists if and only if n k is even. In this paper, we characterize the cycle type of a k-complementing permutation in Sym(n) which has order equal to a power of 2. This yields a test to determine if a nite permutation is a k-complementing permutation, and an algorithm for generating all selfcomplementary k-hypergraphs of order n, up to isomorphism, for feasible n. We also obtain a… Show more

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Cited by 8 publications
(4 citation statements)
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“…Let be as in (I) of Lemma 5. Then = 3, and we may choose = 8 and = (1,8). Recall that every is the union of some -orbits on {3} .…”
Section: The Main Resultsmentioning
confidence: 99%
See 2 more Smart Citations
“…Let be as in (I) of Lemma 5. Then = 3, and we may choose = 8 and = (1,8). Recall that every is the union of some -orbits on {3} .…”
Section: The Main Resultsmentioning
confidence: 99%
“…Then ≤ . It is well-known that = GL( , 2) acts primitively on the set of 2-dimensional subspaces of 2 8) is permutation isomorphic to a 3-homogeneous subgroup of AGL(3, 2) with (1,8) corresponding to (3,2). It follows that { | 1 ≤ ≤ 7} is isomorphic to  (8;3,7) .…”
Section: Lemmamentioning
confidence: 99%
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“…The vertex transitive self-complementary k-uniform hypergraphs are the subject of the paper [11] by Potǒcnik andŠajna. Gosselin gave an algorithm to construct some special self-complementary k-uniform hypergraphs in [3]. In [6] and [10] Knor, Potǒcnik andŠajna study the existence of regular self-complementary k-uniform hypergraphs.…”
Section: Preliminaries and Resultsmentioning
confidence: 99%