1995
DOI: 10.1007/978-94-015-8474-6
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Gaussian Random Functions

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Cited by 315 publications
(214 citation statements)
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“…This computation allows us, in particular, to assert that Dudley integral is finite on Θ. It yields Lifshits (1995) The last inequality shows also that there exist τ > 0 such that for any s ∈ S, satisfying lim sup a→∞ a τ s −1 (a) < ∞, Assumption 3 is fulfilled.…”
Section: Proof Of Theoremmentioning
confidence: 82%
See 1 more Smart Citation
“…This computation allows us, in particular, to assert that Dudley integral is finite on Θ. It yields Lifshits (1995) The last inequality shows also that there exist τ > 0 such that for any s ∈ S, satisfying lim sup a→∞ a τ s −1 (a) < ∞, Assumption 3 is fulfilled.…”
Section: Proof Of Theoremmentioning
confidence: 82%
“…In view of the latter remark we can consider the set Θ those entropy obeys the restriction which is closer to the minimal one (c.f. Sudakov lower bound for gaussian random functions Lifshits (1995)). We note, however, that there exist examples where s has to be chosen on a more special way (see Theorem 1).…”
Section: Discussionmentioning
confidence: 99%
“…Using the continuous functional F (f ) = f ∞ and (26), we obtain: It follows from (27) that µ(L) = 1. By (Lifshits, 1995, Section 9, Proposition 1) H ξ ⊂ L. From Lemma 2 we obtain the following Bernsteintype theorem from approximation theory:…”
Section: 2mentioning
confidence: 88%
“…A standard Gaussian field on E is a collection of random variables {W x ; x ∈ E} any linear combination of which is Gaussian and such that EW x = 0 and EW 2 x = 1 for x ∈ E (see [11] or [12] for more details on Gaussian fields) . The covariance function of W Σ x,y = EW x W y , x, y ∈ E is semi-definite positive.…”
Section: Gaussian Level Sets Covariancesmentioning
confidence: 99%