2008
DOI: 10.1088/0143-0807/29/5/012
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From Moon-fall to motions under inverse square laws

Abstract: The motion of two bodies, along a straight line, under the inverse square law of gravity is considered in detail, progressing from simpler cases to more complex ones: (a) one body fixed and one free, (b) both bodies free and identical mass, (c) both bodies free and different masses and (d) the inclusion of electrostatic forces for both bodies free and different masses. The equations of motion (EOM) are derived starting from Newton's second law or from conservation of energy. They are then reduced to dimensionl… Show more

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Cited by 7 publications
(9 citation statements)
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“…Correspondingly, the quantity representing distance in these equations, either the dimensionless x of equation ( 7) or the dimensional x of equation ( 9), cannot take the value of zero, as is implied by the computations leading to equation ( 8) on page 990 and in the steps performed on examples 2 and 3 on page 993 of the article.In fact, if one considers the interacting bodies as rigid spheres and representing by R T , R M and R S respectively the radius of the Earth, the Moon and the Sun, the lowest value that the dimensional x can take in equation ( 9) is x = (R T + R M ) (interaction Earth-Moon) or x = (R T + R S ) (interaction Earth-Sun). Moreover, the fact that x cannot be zero released the speed of the falling body, in equation ( 6), from taking an infinite value.Nevertheless, when the aforementioned corrections are implemented, the obtained numerical values are very close to the ones reported in the article [1]. Specifically, using the values R T = 6.378 × 10 3 Km, R M = 1.738 × 10 3 Km, R S = 6.960 × 10 5 Km, and the numerical values provided in Foong's paper at the beginning of section 2.6, page 993, the results for the dimensional time, using either equation ( 9) or equation ( 7) and (10) in the paper, are shown in table 1 (computed as if each numerical value has four significant figures): the computed relative percent error indicates that both values are practically the same.…”
supporting
confidence: 82%
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“…Correspondingly, the quantity representing distance in these equations, either the dimensionless x of equation ( 7) or the dimensional x of equation ( 9), cannot take the value of zero, as is implied by the computations leading to equation ( 8) on page 990 and in the steps performed on examples 2 and 3 on page 993 of the article.In fact, if one considers the interacting bodies as rigid spheres and representing by R T , R M and R S respectively the radius of the Earth, the Moon and the Sun, the lowest value that the dimensional x can take in equation ( 9) is x = (R T + R M ) (interaction Earth-Moon) or x = (R T + R S ) (interaction Earth-Sun). Moreover, the fact that x cannot be zero released the speed of the falling body, in equation ( 6), from taking an infinite value.Nevertheless, when the aforementioned corrections are implemented, the obtained numerical values are very close to the ones reported in the article [1]. Specifically, using the values R T = 6.378 × 10 3 Km, R M = 1.738 × 10 3 Km, R S = 6.960 × 10 5 Km, and the numerical values provided in Foong's paper at the beginning of section 2.6, page 993, the results for the dimensional time, using either equation ( 9) or equation ( 7) and (10) in the paper, are shown in table 1 (computed as if each numerical value has four significant figures): the computed relative percent error indicates that both values are practically the same.…”
supporting
confidence: 82%
“…Nevertheless, when the aforementioned corrections are implemented, the obtained numerical values are very close to the ones reported in the article [1]. Specifically, using the values R T = 6.378 × 10 3 Km, R M = 1.738 × 10 3 Km, R S = 6.960 × 10 5 Km, and the numerical values provided in Foong's paper at the beginning of section 2.6, page 993, the results for the dimensional time, using either equation ( 9) or equation ( 7) and (10) in the paper, are shown in table 1 (computed as if each numerical value has four significant figures): the computed relative percent error indicates that both values are practically the same.…”
supporting
confidence: 82%
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“…In mathematics, it would be very difficult to construct a local initial-wavepacket in spatial 3-dimensions (wherein the test particles were dropped), via the superposition of " hydrogen atomic eigenstates". Note that, even in classical mechanics, analytically solving the trajectory of free fall as a function of time is not trivial, which refers to the Inverse Kepler problem [34].…”
Section: Introductionmentioning
confidence: 99%