“…There are four such sums, two of the form 2s + t and two of the form 2t + s. So, applying Theorem 1.1, if m 3 s,t is in the balanced cone of multiplicities, it is free if and only if 6(s − t) 2 ≤ 4 · 3, or |s − t| ≤ 1. In fact, using the classification from [8], it follows that m 3 s,t is a free multiplicity if and only if |s − t| ≤ 1 (regardless of whether m 3 s,t is in the balanced cone or not). Example 1.4.…”