“…A term t l can be analysed by finding a Γ and ϕ such that Γ, ϕ |= t l . This is done by solving the 6 2 , @ (7,2) } Γ(11) = {F 10 1 , @ (10,9) , @ (17,8) , @ (7,2) } ϕ(13) = true ϕ(15) = true Γ, ϕ |= (S 15 @ 16 (F 13 @ 14 F 12 )@ 17 (F 10 @ 11 F 9 ))@ 18 (S 6 @ 7 (F 4 @ 5 F 3 )@ 8 (F 1 @ 2 F 0 )) Figure 8: Solution of the analysis for application of identity to itself in SF-calculus.…”