2021
DOI: 10.21538/0134-4889-2021-27-1-240-245
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Finite totally k-closed groups

Abstract: For a positive integer k, a group G is said to be totally k-closed if in each of its faithful permutation representations, say on a set Ω, G is the largest subgroup of Sym(Ω) which leaves invariant each of the Gorbits in the induced action on Ω × • • • × Ω = Ω k . We prove that every abelian group G is totally (n(G) + 1)-closed, but is not totally n(G)closed, where n(G) is the number of invariant factors in the invariant factor decomposition of G. In particular, we prove that for each k ≥ 2 and each prime p, t… Show more

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Cited by 5 publications
(4 citation statements)
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“…Theorem 1.1 generalizes recent results of [2,3], where similar theorems were proved for 2-closures of nilpotent groups [2] and for k-closures of abelian groups [3]. It is worth mentioning that nilpotency of k-closure of nilpotent group is already known and it easily follows from [2, Thm.…”
supporting
confidence: 80%
“…Theorem 1.1 generalizes recent results of [2,3], where similar theorems were proved for 2-closures of nilpotent groups [2] and for k-closures of abelian groups [3]. It is worth mentioning that nilpotency of k-closure of nilpotent group is already known and it easily follows from [2, Thm.…”
supporting
confidence: 80%
“…In previous work it has been shown that k(G) = 2 if G is a cyclic group of prime order [13, Theorem 1.2], and for exactly six nonabelian simple groups [3, Theorem 1.1], namely the Janko groups J 1 , J 3 and J 4 , together with Ly, T h and the Monster M. By (1), k(G) ≥ 3 for all other finite simple groups. The problem of determining the closure number k(G) for the remaining simple groups was posed in [3, Question 3], and in particular for determining all those with closure number 3 (if any exist), see also [13,Problem 3] and the Kourovka Notebook [19,New Problems 20.2 and 20.3].…”
Section: Introductionmentioning
confidence: 99%
“…In this paper we study the closure numbers for finite simple groups. In previous work it has been shown that k(G) = 2 if G is a cyclic group of prime order [12,Theorem 1.2], and for exactly six nonabelian simple groups [2, Theorem 1.1], namely the Janko groups J 1 , J 3 and J 4 , together with Ly, T h and the Monster M. By (1), k(G)…”
Section: Introductionmentioning
confidence: 99%
“…3 for all other finite simple groups. The problem of determining the closure number k(G) for the remaining simple groups was posed in [2, Question 3], and in particular for determining all those with closure number 3 (if any exist), see also [12,Problem 3] and the Kourovka Notebook [18,New Problems 20.2 and 20.3].…”
Section: Introductionmentioning
confidence: 99%