2006
DOI: 10.1017/s1446788700014348
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Filter games and pathological subgroups of a countable product of lines

Abstract: To each filter & on co, a certain linear subalgebra A (^) of R™, the countable product of lines, is assigned. This algebra is shown to have many interesting topological properties, depending on the properties of the filter &. For example, if & is a free ultrafilter, then A(^) is a Baire subalgebra of R" for which the game OF introduced by Tkachenko is undetermined (this resolves a problem of Hernandez, Robbie and Tkachenko); and if & x and ^2 are two free filters on a> that are not near coherent (such filters … Show more

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Cited by 5 publications
(13 citation statements)
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References 19 publications
(62 reference statements)
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“…and results similar to these, were previously obtained in [4,25,5] and possibly in additional places.…”
Section: The Hurewicz and Menger Conjectures Revisitedsupporting
confidence: 92%
“…and results similar to these, were previously obtained in [4,25,5] and possibly in additional places.…”
Section: The Hurewicz and Menger Conjectures Revisitedsupporting
confidence: 92%
“…is not provably preserved under cartesian products [5,34,65]. If G is analytic and does not satisfy S 1 (Ω nbd , Γ), then G 2 does not satisfy S fin (O nbd , O).…”
Section: Topological Groupsmentioning
confidence: 99%
“…Question 1 of Banakh, Nickolas, and Sanchis [5] asks whether each Mengerbounded subgroup of C N (with coordinate-wise addition) is mixable or o F -bounded for some filter F. As it is proved there that mixable Menger-bounded groups are Scheepers bounded, and the same holds for groups which are o F -bounded for some filter F, we obtain a negative answer to both questions: The groups we construct are, in particular, subgroups of C N . The problem of whether, consistently, every Menger-bounded group is Scheepersbounded is yet to be addressed.…”
Section: Lemma 5 G K Is Menger-bounded If and Only If For Each Seqmentioning
confidence: 99%