Few-nucleon transfer reactions on 15N and 16O

Rae, W.D.M.; Godwin, N.S.; Sinclair, D.K.; Bradlow, H.S.; Fisher, Peter; King, J.D.; Pilt, A.A.; Proudfoot, G.

doi:10.1016/0375-9474(79)90184-2

Cited by 27 publications

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References 22 publications

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“…Most remarkably, the same selective population of certain state was essentially the same under the change of energy or reaction. Very significant is the fact that essentially identical spectra was found in all the helion transfer studies by different groups: 12 C( 6 Li, t) 15 O; 12 C( 11 B, 8 Li) 15 O, 12 C( 12 C, 9 Be) 15 O [30,31]. Hence they concluded [29] that these reactions represent a powerful reaction-mechanism-independent method of finding corresponding analogue states in the residual nuclei.…”

Section: Further Support For Su (2)a Nusospin Symmetrymentioning

confidence: 75%

A = 3 Clustering in Nuclei

Abbas

Ahmad

2011

Int. J. Mod. Phys. E

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Alpha clustering in nuclei, at present is a well studied and reasonably well accepted property of the nucleus. Less well appreciated and more ambiguous is the role of A = 3 clustering, i.e. helion and triton, in nuclei. Here we try to place A = 3 clustering in nuclei into its proper perspective, first by pointing out strong experimental evidences which indicate its clear presence in nuclei and secondly showing as to how to include these A = 3 clusters in a proper and consistent theoretical understanding of the nuclear phenomenon. * Electronic address: afsarabbas@yahoo.com

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Section: Further Support For Su (2)a Nusospin Symmetrymentioning

confidence: 75%

A = 3 Clustering in Nuclei

Abbas

Ahmad

2011

Int. J. Mod. Phys. E

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“…The last term describes the doublet splittings with a single parameter for each doublet. This equation is standard [22,23] for the energies of states constructed by coupling single particles to cores with J c ࣔ 0. In Ref.…”

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confidence: 99%

Lowest negative-parity states inBe12

Fortune

2014

Phys. Rev. C

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A very simple model is applied to the first four negative-parity states of 12 Be. Energies of the corresponding four states in 14 C are used to validate the model and to determine the doublet splitting parameters. Predictions for 12 Be are in remarkable agreement with excitation energies of the known 1 − at 2.70 MeV and the suspected (3 − ) at 4.56 MeV. Predicted excitation energies of 0 − and 2 − are 3.59 and 5.12 MeV, respectively.Introduction. In 12 Be, adding 2s 1/2 and 1d 5/2 neutrons to the first-excited state of 11 Be at 0.320 MeV [1] produces four negative-parity states, with J = 0 to 3. Of these, only the 1 − state at E x = 2.702 MeV [2] has been definitely identified. A candidate for the 3 − state is at 4.56 MeV. This state was initially suggested as 2 + [3], but it now appears likely [4,5] to be (3 − ) or a (3 − /2 + ) doublet. Millener [4] noted the excellent agreement between the 1.86 MeV energy difference between the 1 − and the probable (3 − ) in 12 Be and the 1/2 + -5/2 + splitting of 1.78 MeV in 11 Be. Comparison of heavy-ion-induced reactions leading to 12 Be [6,7] and 14 C [8] (where the 3 − is known) significantly strengthens the 3 − suggestion for the 4.56-MeV state. The suggestion [9] that the (3 − ) state might instead be 0 + has been addressed recently [10,11]. Nothing is known about possible 0 − and 2 − states, whose unnatural parity would have caused them to be very weak in the 10 Be(t,p) reaction. They were also not observed in two different investigations [12,13] of the 11 Be(d,p) reaction (in reverse kinematics), even though the 0 − spectroscopic factor is predicted [12] to be reasonably large. The possibility that the 0 − might be an isomer [14] depends on its energy relative to the neutron breakup threshold at 3.171 MeV [15].Various calculations have predicted the energy of the 0 − state. 16] produced a 0 − excitation energy of about 2.5 to 2.8 MeV. They had adjusted their potential to reproduce the ground state (g.s.) energy. They then found that they missed the energies of the second 0 + and first 2 + states by 0.84 and 0.92 MeV, respectively, which they fixed by adjusting a three-body force. They found they needed no three-body force for the 1 − state and hence used none for 0 − . Kanada-En'yo and Horiuchi [17] had predicted the 0 − to be very unbound, with E x ß 8-9 MeV, but they had the first 1 − above 5 MeV, and it is known at 2.7 MeV. Blanchon et al.[18] obtained an excitation energy of 2.91 MeV. Garrido et al. [9] have it at about 3.19 MeV. Kanungo et al.[12] calculated a 0 − energy at 5.59-5.91, but their energy of the 1 − state was 3.38-3.71 MeV. These predictions are summarized in Table I. A no-core shell-model calculation [19] considered only the first few states of 12 Be and thus provided no prediction for 0 − . Descouvement and Baye [20] calculated only natural-parity states and therefore had no 0 − prediction.In 14 C, four states with J π = 0 − to 3 − are known [21] and can be thought of as s and d neutrons coupled to the 1/2 − ground state (g.s.) of 13 C. Our aim h...

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