2018
DOI: 10.1007/s00453-018-0466-x
|View full text |Cite
|
Sign up to set email alerts
|

Faster Algorithms for Security Games on Matroids

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
1
1

Citation Types

0
6
0

Year Published

2018
2018
2024
2024

Publication Types

Select...
4

Relationship

0
4

Authors

Journals

citations
Cited by 4 publications
(6 citation statements)
references
References 19 publications
0
6
0
Order By: Relevance
“…holds for each edge e. Now assume that the Defender uses the following mixed strategy: for every 1 ≤ i ≤ t she assigns the probability α i to P i and 0 to the rest of the st-paths. Then if the Attacker targets an edge e then her expected loss is α i − c(e) ≤ d(e) (µp(e) + q(e)) − c(e) = µ by (2). Therefore this mixed strategy guarantees the Defender an expected loss of at most µ.…”
Section: Preliminaries On Game Theorymentioning
confidence: 91%
See 3 more Smart Citations
“…holds for each edge e. Now assume that the Defender uses the following mixed strategy: for every 1 ≤ i ≤ t she assigns the probability α i to P i and 0 to the rest of the st-paths. Then if the Attacker targets an edge e then her expected loss is α i − c(e) ≤ d(e) (µp(e) + q(e)) − c(e) = µ by (2). Therefore this mixed strategy guarantees the Defender an expected loss of at most µ.…”
Section: Preliminaries On Game Theorymentioning
confidence: 91%
“…Furthermore, in the special case of c(e) ≡ 0 the result of [16,Corollary 51.8a] is essentially equivalent to the above theorem in a non-game-theoretical setting. The running time of the algorithm given in [17] was later substantially improved to O(|V | 4 |E| 1 2 ) in [2]. It also follows from the above theorem that the spanning tree game is capable of capturing a known graph reliability metric.…”
Section: Theoremmentioning
confidence: 99%
See 2 more Smart Citations
“…Since this game is a two-player, zero-sum game, it has a unique Nash-equilibrium payoff (or, in simpler terms, game value) V by Neumann's classic Minimax Theorem. Since V is the highest expected gain the Attacker can guarantee himself by an appropriately chosen mixed strategy (that is, probability distribution on the set of edges), it makes sense to say that 1 V is a valid reliability metric. After some preliminary results on some special cases in the literature (see [14] for the details), the Spanning Tree Game was solved in the above defined general form in [13].…”
Section: An Application: Reliability Of Network Via Game Theorymentioning
confidence: 99%