2019
DOI: 10.1088/1361-6463/ab1014
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Experimental derivation of Arrhenius equations for collisional quenching rate coefficients of Ar(3P2) by Ar(1S0) and H2O

Abstract: This paper presents the temperature dependence for the collisional quenching rate coefficient of the metastable excited atom Ar(3P2) by the water molecule H2O. A few papers reported on the collisional quenching rate coefficients of the metastable excited atom Ar(3P2) by the ground state atom Ar(1S0) and the water vapor molecule (H2O) have already been published; however, their temperature dependences have not been reported. We determined them experimentally by a nonspectroscopic method following our previous w… Show more

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Cited by 6 publications
(3 citation statements)
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References 39 publications
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“…We reported 15 that N 2 (A 3 ∑ u + ) de‐excites in collision with H 2 O having the energy level diagram shown in Figure 3(C) (ionization above 15 eV is omitted) and measured rate coefficient of this reaction 16 ; eventually, this contributes to OH generation in Figure 3(D). On the other hand, we also measured rate coefficient of the collisional quenching of Ar( 3 P 2 ) by H 2 O 17 . Emission produced by excited state of OH due to H 2 O dissociation has a peak at 309 nm caused by the transition OH(A 2 ∑ + , v = 0) → OH(X 2 Π, v = 0); this is shown by brown and classified with Group VI.…”
Section: Resultsmentioning
confidence: 99%
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“…We reported 15 that N 2 (A 3 ∑ u + ) de‐excites in collision with H 2 O having the energy level diagram shown in Figure 3(C) (ionization above 15 eV is omitted) and measured rate coefficient of this reaction 16 ; eventually, this contributes to OH generation in Figure 3(D). On the other hand, we also measured rate coefficient of the collisional quenching of Ar( 3 P 2 ) by H 2 O 17 . Emission produced by excited state of OH due to H 2 O dissociation has a peak at 309 nm caused by the transition OH(A 2 ∑ + , v = 0) → OH(X 2 Π, v = 0); this is shown by brown and classified with Group VI.…”
Section: Resultsmentioning
confidence: 99%
“…We estimated the rate coefficient of this collisional quenching reaction as follows 17 kbadbreak=2.75goodbreak×10100.33emcm3/normals$$\begin{equation}k = 2.75 \times 10^{ - 10}\ {\mathrm{cm}}^3/{\mathrm{s}}\end{equation}$$…”
Section: Resultsmentioning
confidence: 99%
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