“…However, we briefly show that we also have Z =Z in this case. Example E (24) : SU (3) 21 ⊂ (E 7 ) 1 : The corresponding modular invariant reads Z E (24) = |χ (0,0) + χ (21,0) + χ (21,21) + χ (8,4) + χ (17,4) + χ (17,13) +χ (11,1) + χ (11,10) + χ (20,10) + χ (12,6) + χ (15,6) + χ (15,9) | 2 +|χ (6,0) + χ (21,6) + χ (15,15) + χ (15,0) + χ (21,15) + χ (6,6) +χ (11,4) + χ (17,7) + χ (14,10) + χ (11,7) + χ (14,4) + χ (17,10) (21,21) ] ⊕ [λ (8,4) ] ⊕ [λ (17,4) ] ⊕ [λ (17,13) ]…”