1994
DOI: 10.1016/0921-4526(94)90213-5
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Excitations in superfluid 4He and the condensate

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Cited by 11 publications
(15 citation statements)
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References 27 publications
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“…Several methods of determination of the wave function (WF) Ψ 0 of the ground state (GS) of helium-II are available [8][9][10][11][12][13][14][15][16][17][18][19][20] (see also reviews [21][22][23]). In order not to take the boundaries into account, they used periodic boundary conditions (BCs) with passing to the T-limit.…”
Section: Ground State Of He Ii: Equationsmentioning
confidence: 99%
See 1 more Smart Citation
“…Several methods of determination of the wave function (WF) Ψ 0 of the ground state (GS) of helium-II are available [8][9][10][11][12][13][14][15][16][17][18][19][20] (see also reviews [21][22][23]). In order not to take the boundaries into account, they used periodic boundary conditions (BCs) with passing to the T-limit.…”
Section: Ground State Of He Ii: Equationsmentioning
confidence: 99%
“…However, the structure of (62) is the assumption, though no solution with another structure was found. The solution for ψ k with "shadow" variables [17,18] is equivalent to (62), (63).…”
Section: Excited State Of He IImentioning
confidence: 99%
“…1-3͒ has shown to be a powerful tool in the investigation of quantum solids and liquids obeying Bose statistics. In the context of variational Monte Carlo ͑VMC͒ calculations, it has allowed for studying many properties of superfluid and solid 4 He: the crystallization, 3,4,10 the excitation spectrum both at zero 5 and at finite temperature, 6,7 the properties of the roton at finite temperature, 8 and the liquid-solid coexistence. 9 In this work we apply the shadow wave function ideas to the ground state of a Fermi system.…”
Section: Introductionmentioning
confidence: 99%
“…We assume that the λ-transition in the bulk He-II is accompanied by complete exhaustion of the one-particle condensate. According to the calculation [27], the fraction of the one-particle condensate is n 0 = 0.078 at T = 0, and n 0 = 0.058 at T = T λ = 2.17 K, i.e., the condensate does not vanish completely at T = T λ , although n 0 (T λ ) ≈ 0 in the experiment. It is suggested in [27] that the one-particle condensate in He-II is exhausted completely [n 0 (T λ ) = 0] because of vortex rings.…”
Section: On the Possibility Of A Jump In The Curve T M (D)mentioning
confidence: 94%
“…According to the calculation [27], the fraction of the one-particle condensate is n 0 = 0.078 at T = 0, and n 0 = 0.058 at T = T λ = 2.17 K, i.e., the condensate does not vanish completely at T = T λ , although n 0 (T λ ) ≈ 0 in the experiment. It is suggested in [27] that the one-particle condensate in He-II is exhausted completely [n 0 (T λ ) = 0] because of vortex rings. The rings were not taken into account in the calculation of [27], and the decrease in n 0 at T → T λ was due to rotons: the number of the atoms pulled out of the condensate was directly proportional to the number of rotons.…”
Section: On the Possibility Of A Jump In The Curve T M (D)mentioning
confidence: 94%