2012
DOI: 10.1007/s00285-012-0615-9
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Exact formulas for the variance of several balance indices under the Yule model

Abstract: One of the main applications of balance indices is in tests of nullmodels of evolutionary processes. The knowledge of an exact formula for a statistic of a balance index, holding for any number n of leaves, is necessary in order to use this statistic in tests of this kind involving trees of any size. In this paper we obtain exact formulas for the variance under the Yule model of the Sackin, the Colless and the total cophenetic indices of binary rooted phylogenetic trees with n leaves.

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Cited by 25 publications
(35 citation statements)
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References 27 publications
(33 reference statements)
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“…• A tree of shape Q * 3 can only be obtained by adding the leaf 4 to the arc from the root to its only leaf child in some tree K Since E Y (QIB 1 ) = 0 and f QIB (n − 1, 1) = 0, applying the aforementioned result from [4] we have that Dividing by n both sides of this expression for E Y (QIB 2 n ) and setting y n = E Y (QIB 2 n )/n, we obtain the recurrence y n = y n−1 + (n − 2)(n − 3)(253n 4 − 2014n 3 + 6119n 2 − 7430n + 3504) 181440…”
Section: Discussionmentioning
confidence: 99%
“…• A tree of shape Q * 3 can only be obtained by adding the leaf 4 to the arc from the root to its only leaf child in some tree K Since E Y (QIB 1 ) = 0 and f QIB (n − 1, 1) = 0, applying the aforementioned result from [4] we have that Dividing by n both sides of this expression for E Y (QIB 2 n ) and setting y n = E Y (QIB 2 n )/n, we obtain the recurrence y n = y n−1 + (n − 2)(n − 3)(253n 4 − 2014n 3 + 6119n 2 − 7430n + 3504) 181440…”
Section: Discussionmentioning
confidence: 99%
“…Value rQI vs S on BT20 −0.889 rQI vs C on BT20 −0.893 rQI vs Φ on BT20 −0.935 rQI vs Ch on BT20 0.165 rQI vs S on T15 −0.787 rQI vs Φ on T15 −0.827 Since E Y (rQIB 1 ) = 0 and f rQIB (n − 1, 1) = 0, applying the aforementioned result from [5] we have that Dividing by n both sides of this expression for E Y (rQIB 2 n ) and setting y n = E Y (rQIB 2 n )/n, we obtain the recurrence y n = y n−1 + (n − 2)(n − 3)(253n 4 − 2014n 3 + 6119n 2 − 7430n + 3504) 181440 .…”
Section: Correlationmentioning
confidence: 98%
“…3.1) Since QB(10) = {(5, 5), (6, 4)}, the different ways of splitting the leaves of the tree (10, 10) produce the trees ((5, 5), (5, 5)), ((5, 5), (6,4)), and ((6, 4), (6,4)). Now, since QB(5) = {(3, 2)}, QB(6) = {(3, 3), (4, 2)}, and QB(3) = {(2, 1)}, and 1, 2, and 4 are powers of 2, we have the following derivations from these trees through all possible combinations of splitting the leaves in the trees:…”
Section: Characterizing and Generating Minimal Colless Treesmentioning
confidence: 99%
“…((5, 5), (5,5)) ⇒ (((3, 2), (3, 2)), ((3, 2), (3, 2))) ⇒ ((((2, 1), 2), ((2, 1), 2)), (((2, 1), 2), ((2, 1), 2))) ⇒ (((((·, ·), ·), (·, ·)), (((·, ·), ·), (·, ·))), ((((·, ·), ·), (·, ·)), (((·, ·), ·), (·, ·)))) ((5, 5), (6,4)) ⇒ (((3, 2), (3, 2)), ((3, 3), 4)) ⇒ ((((2, 1), 2), ((2, 1), 2)), (((2, 1), (2, 1)), 4)) ⇒ (((((·, ·), ·), (·, ·)), (((·, ·), ·), (·, ·))), ((((·, ·), ·), ((·, ·), ·)), ((·, ·), (·, ·))) ((5, 5), (6,4)) ⇒ (((3, 2), (3, 2)), ((4, 2), 4)) ⇒ ((((2, 1), 2), ((2, 1), 2)), ((4, 2), 4)) ⇒ (((((·, ·), ·), (·, ·)), (((·, ·), ·), (·, ·))), ((((·, ·), (·, ·)), (·, ·)), ((·, ·), (·, ·)))) ((6, 4), (6,4)) ⇒ (((3, 3), 4), ((3, 3), 4)) ⇒ ((((2, 1), (2, 1)), 4), (((2, 1), (2, 1)), 4)) ⇒ (((((·, ·), ·), ((·, ·), ·)), ((·, ·), (·, ·))), ((((·, ·), ·), ((·, ·), ·)), ((·, ·), (·, ·)))) ((6, 4), (6,4)) ⇒ (((3, 3), 4), ((4, 2), 4)) ⇒ ((((2, 1), (2, 1)), 4), ((4, 2), 4)) ⇒ (((((·, ·), ·), ((·, ·), ·)), ((·, ·), (·, ·))), ((((·, ·), (·, ·)), (·, ·)), ((·, ·), (·, ·)))) ((6, 4), (6,4)) ⇒ (((4, 2), 4), ((4, 2), 4)) ⇒ (((((·, ·), (·, ·)), (·, ·)), ((·, ·), (·, ·))), ((((·, ·), (·, ·)), (·, ·)), ((·, ·), (·, ·)))) (2, 1), (2, 1)), ((2, 1), (2, 1))), 8) ⇒ (((((·, ·), ·), ((·, ·), ·)), (((·, ·), ·), ((·, ·), ·))), (((·, ·), (·, ·)), ((·, ·), (·, ·)))) ((6, 6), 8) ⇒ (((3, 3), (4, 2)), 8) ⇒ ((((2, 1), (2, 1)), (4, 2)), 8) ⇒ (((((·, ·), ·), ((·, ·), ·)), (((·, ·), (·, ·)), (·, ·))), (((·, ·), (·, ·)), ((·, ·), (·, ·)))) ((6, 6), 8) ⇒ (((4, 2), (4, 2)), 8) ⇒ (((((·, ·), (·, ·)), (·, ·)), (((·, ·), (·, ·)), (·, ·))), (((·, ·), (·, ·)), ((·, ·), (·, ·)))) ((8, 4), 8) ⇒ (((((·, ·), (·, ·)), ((·, ·), (·, ·))), ((·, ·), (·, ·))), (((·, ·), (·, ·)), ((·, ·), (·, ·)))) So, there are 10 different minimal Colless trees in T 20 . We depict them in Figure 5 below.…”
Section: Characterizing and Generating Minimal Colless Treesunclassified
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