“…Following an analogous procedure from 1.8 g (9.2 mmol) of the intermediate obtained from 0.47 g (20.4 mmol) of metallic sodium, 1 g (10.64 mmol) of 1,3propanethiol and 1.64 g (20.38 mmol) of 2-chloroethanol, 1.26 g of 7b was obtained as a yellow oil (1.27 g, 5.45 mmol, 59% yield, 77% purity as determined by 1 H NMR). 1 H NMR (CDCl 3 ) δ: 1.88 (q, J = 6 Hz, 2H, CH 2 ], 2.69 (t, J = 6 Hz, 4H, CH 2 ), 2.86 (t, J = 6 Hz, 4H, CH 2 ), 3.64 (t, J = 6 Hz, 4H, CH 2 ) MS (EI, 70 eV) m/z (%B): 232(M + , 8), 196(9), 169(100), 133 (17), 107(33), 87(20), 73 (34), 63 (23), 45 (21) Bis(2-chloroethylthioethyl)ether, 8. To a solution of metallic sodium (17 mmol, 0.39 g) in 20 mL of absolute EtOH, 2mercaptoethanol (net, 16 mmol, 1.25 mL) was added dropwise under an argon atmosphere.…”