Articles you may be interested inVibrational distributions of KrF(B) and XeCl(B) produced from ionicrecombination reactions of Kr+(2 P 3/2)+SF− 6 and Xe+(2 P 3/2)+Cl−+He Rovibrational distributions of CH(A 2Δ) produced in energytransfer reactions from Ar(3 P 2), Kr(3 P 2), and Xe(3 P 2) atoms to C2H5 radical Energy-transfer reactions from ArCP 2 ), KrCP 2 ), and XeCP 2 ) to CH 3 radical have been studied by observing emission spectra from excited fragments in the flowing afterglow. CH 3 radicals were generated by the F + CH 4 reaction. The CH(A 2a-X2IIr:v' = 0 -2) and CH(B 2~ --X 2 II r :v' = 0) emission systems were observed in the ArCP 2 ) reaction, while only CH(A-X:v' = 0,1) emission system was found in the KrCP 2 ) and XeCP 2 ) reactions. The nascent rovibrational distributions of CH(A:v' = 0-2) were No :N 1 :N 2 = l00( To = 3400 ± 400 K):28 ± 5(T 1 = 1700 ± 400 K):4 ± l(T 2 = 700 ± 300 K) in the ArCP 2 ) reaction and l00( To' = 1000 ± 250 K): < 5 (T 1 < 800 K):O in the Kr( 3 P 2 ) and Xe ( 3 P2 ) reactions. The rotational distribution of CH(B:v' = 0) in the ArCP 2 ) reaction was reproduced by a single Boltzmann temperature of 2800 ± 300 K. The average fractions of total available energies channeled into vibration and rotation ofCH (A,B) were less than 15% for all cases, suggesting that most of the available energies was deposited as relative translational energy of products and/or rovibrational energy ofH 2 • The observed rovibrational distributions of CH (A) were colder than those predicted from statistical theories including and excluding the conservation of total angular momentum. The best agreement between the observed and statistical distributions was obtained for the mechanism giving CH(A,B) in two-body dissociation steps by assuming that 78-92% of the total available energy is released as kinetic energy in the first step, Rgep 2 ) + CH 3 --CHt + Rg, then the rest remains in the precursor CHr state as an internal energy. CH 4 , CF 4 , and Ar in the discharge tube were 0.01-0.015, J. Chern. Phys. 95 (10),