2001
DOI: 10.1007/s00454-001-0008-0
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Equivelar Polyhedra with Few Vertices

Abstract: We know that the polyhedra corresponding to the Platonic solids are equivelar. In this article we have classified completely all the simplicial equivelar polyhedra on ≤ 11 vertices. There are exactly 27 such polyhedra. For each n ≥ −4, we have classified all the ( p, q) such that there exists an equivelar polyhedron of type { p, q} and of Euler characteristic n. We have also constructed five types of equivelar polyhedra of Euler characteristic −2m, for each m ≥ 2.

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Cited by 17 publications
(728 citation statements)
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“…Now, {2, 3, 4} is a face of N 1 but ϕ({2, 3, 4}) = {1, 2, 6} is not a face of N 3 , a contradiction. If ϕ(1) = 9 then from lk N 1 (0), lk N 1 (1), lk N 3 (0) and lk N 3 (9), we get ϕ = (1, 9, 5, 3, 7)(2, 10) (4,8). Now, {5, 7, 11} is a face of N 1 but ϕ({5, 7, 11}) = {1, 3, 11} is not a face of N 3 , a contradiction.…”
Section: Examples and Preliminariesmentioning
confidence: 99%
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“…Now, {2, 3, 4} is a face of N 1 but ϕ({2, 3, 4}) = {1, 2, 6} is not a face of N 3 , a contradiction. If ϕ(1) = 9 then from lk N 1 (0), lk N 1 (1), lk N 3 (0) and lk N 3 (9), we get ϕ = (1, 9, 5, 3, 7)(2, 10) (4,8). Now, {5, 7, 11} is a face of N 1 but ϕ({5, 7, 11}) = {1, 3, 11} is not a face of N 3 , a contradiction.…”
Section: Examples and Preliminariesmentioning
confidence: 99%
“…, where α = (0, 4, 8)(1, 5, 9)(2, 6, 10) (3,7,11), β = (0, 2)(4, 10)(1, 11)(3, 9)(5, 7) (6,8), α 1 = (1, 2)(3, 4)(5, 6)(7, 8)(9, 10)(11, 0), α 2 = (1, 3)(2, 4)(5, 7)(6, 8)(9, 11)(10, 0) and γ = (1, 2)(3, 4)(5, 6)(7, 8)(9, 10).…”
Section: Examples and Preliminariesmentioning
confidence: 99%
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