2011
DOI: 10.4310/joc.2011.v2.n1.a6
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Enumerating $(\bf{2+2})$-free posets by indistinguishable elements

Abstract: A poset is said to be (2 + 2)-free if it does not contain an induced subposet that is isomorphic to 2 + 2, the union of two disjoint 2-element chains. Two elements in a poset are indistinguishable if they have the same strict up-set and the same strict down-set. Being indistinguishable defines an equivalence relation on the elements of the poset. We introduce the statistic maxindist, the maximum size of a set of indistinguishable elements. We show that, under a bijection of Bousquet-Mélou et al. [1], indisting… Show more

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Cited by 25 publications
(38 citation statements)
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“…We refine the set P n (12123) as follows. Given n ≥ 2 and 1 ≤ s < t ≤ n, let A n,t,s denote the subset of P n (12123) consisting of those partitions π = π 1 π 2 · · · π n having at least two distinct letters in which the left-most occurrence of the largest letter is at position t and the left-most occurrence of the second largest letter is at position s. For example, π = 123324425215 ∈ A 12,9,6 since the left-most occurrence of the largest letter, namely, 5, is at position 9 and the left-most occurrence of the second largest letter is at position 6. The array a n,t,s = |A n,t,s | is determined by the following recurrence.…”
Section: The Case 1012mentioning
confidence: 99%
“…We refine the set P n (12123) as follows. Given n ≥ 2 and 1 ≤ s < t ≤ n, let A n,t,s denote the subset of P n (12123) consisting of those partitions π = π 1 π 2 · · · π n having at least two distinct letters in which the left-most occurrence of the largest letter is at position t and the left-most occurrence of the second largest letter is at position s. For example, π = 123324425215 ∈ A 12,9,6 since the left-most occurrence of the largest letter, namely, 5, is at position 9 and the left-most occurrence of the second largest letter is at position 6. The array a n,t,s = |A n,t,s | is determined by the following recurrence.…”
Section: The Case 1012mentioning
confidence: 99%
“…Remarkably, the set of transitive web worlds is in one-to-one correspondence with the (2 + 2)-free posets. It seems likely that this connection will engender some interesting results, given the fast growing literature on these posets (see [1,2,4,6,5] for references).…”
Section: Introductionmentioning
confidence: 99%
“…We have used Mathematica to compute the first few terms of A (p) (t, z) for p = 2, 3, 4: Next we can use the same techniques as in [4] to find the generating function for the number of primitive p-ascent sequences. That is, let r n,p denote the number of p-ascent sequences a of length n such that a has no consecutive repeated letters and a n,p denote the number of p-ascent sequences a of length n. If R (p) (t) = 1 + n≥1 r n,p t n and A (p) (t) = 1 + n≥1 a n,p t n , then it is easy to see that…”
Section: Resultsmentioning
confidence: 99%