2011
DOI: 10.1524/anly.2011.1125
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Entire functions sharing one value with linear differential polynomials

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Cited by 2 publications
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“…Since by the hypothesis E 1) (a; L (1) ) ⊂ E(a; f ), we get E(a; L (1) ) = E(a; f ). Since E(a; L (1) ) = E(a; f ) = E 1) (a; f ) ⊂ E(a; f (1) ) and from (3.3) we get L (3) = φ f (1) , each a-point of L (1) is a double a-point. Therefore, (3.12)…”
Section: Proof Of Theorem 17mentioning
confidence: 97%
“…Since by the hypothesis E 1) (a; L (1) ) ⊂ E(a; f ), we get E(a; L (1) ) = E(a; f ). Since E(a; L (1) ) = E(a; f ) = E 1) (a; f ) ⊂ E(a; f (1) ) and from (3.3) we get L (3) = φ f (1) , each a-point of L (1) is a double a-point. Therefore, (3.12)…”
Section: Proof Of Theorem 17mentioning
confidence: 97%