Entanglement controlled single-electron transmittivity

Abstract

We show that the electron transmittivity of single electrons propagating along a 1D wire in the presence of two magnetic impurities is affected by the entanglement between the impurity spins. For suitable values of the electron wave vector, there are two maximally entangled spin states which respectively make the wire completely transparent whatever the electron spin state, or strongly inhibits electron transmission.

Physical model for the generation of ideal resources in multipartite quantum networking

“…In Refs. [6,14] it was shown that, under such working conditions, the dynamics takes place as if the static particles all occupy the same site, i.e., …”

Transmission Properties of the One-Dimensional Array of Delta Potentials

“…In this situation, the effective mass is 0.067 times the electron mass, and the strengths of interaction are J 1 = J 2 ≃ 1 eVÅas reported for magnetic impurities 11,19 . Figure 4 shows the transmission probability as a function of the electron energy if the distance between impurities is x 1 − x 2 = 1000Å.…”

“…Thus, the study of electron scattering by impurities in quantum wires, using deltapotentials has been a subject of great interest in recent years 6,7,8,9 . In solid state quantum computation, finite δ-function potentials arrays are often used to describe an instantaneous interaction between flying qubits and statics qubits 10,11,12 .…”

Determination of the noise parameters in a one-dimensional open quantum system

“…This is the first step in a framework analogous to that in [13]. There the authors considered an isolated system in which an electron propagates in a one-dimensional wire interacting magnetically with two spin-1/2 impurities at x = 0 and at x = x 0 , and they analyzed the dependence of the electron's transmittivity on the impurities' states.…”

“…The zeroth order term in (13) vanishes because of the orthogonality of |ψ 3 to the spin states of the eigenstate |E , whereas the Hamiltonian term is always zero on the eigenstates, so we are left with…”