Energy-pooling reactions

Computational Study of Resonantly Ionizing Rubidium Vapor by Nanosecond Laser Pulses

“…Calculations are carried out by solving numerically the set of rate Equations (1) to (11), for the exact resonance excitation of one-photon transitions of rubidium atoms between 5S 1/2 → 5P 3/2 or 5S 1/2 → 5P 1/2 under the experimental conditions of Bakhramov et al [15]. Numerical simulations were performed for the different experimentally tested values of both initial rubidium atoms and laser radiation intensities, to study the mutual competition between the multi-photon ionization and the different collisional ionization processes and its contributions to the plasma generated during the interaction.…”

“…For such an excitation, the ionization of the vapor is only partial and does not exceed few percent. This model is improved by introducing the energy pooling and Penning ionization processes into the ionization scheme [11]. The spectroscopic observations of laser-produced plasmas in alkali-metal vapors induced by two-photon resonances using 10 ns pulsed laser have been reported [12].…”

Energy transfer reaction K(4s) + K(7s) → K(4s) + K(5f), theory compared with experiment

“…Characteristics of atomic collisions are also crucial in some branches of technology in order to asses either a positive or negative impact of collision initiated processes. For example, in the field of laser construction projects, the operation principles of the collision lasers operating on atomic transitions, are directly founded on ET collisions [4], while the development of the high-power diode-pumped alkali vapour lasers [5] may suffer from an ET process, which is energy pooling (EP) [6,7].…”

“…In the last few decades, a lot of work has been done on reactions of energy pooling (EP) 1 , mentioned above, (and perhaps less on reverse energy pooling), also with participation of potassium, e.g., [7,[15][16][17][18].…”

“…The EP reaction starts with two colliding atoms (A and B in reaction (2)), both initially in excited states, and ends up with one atom in a highly excited state, and the other in the ground state[7].…”