2015
DOI: 10.1016/j.energy.2015.04.035
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Energy and exergy analysis of LPG (liquefied petroleum gas) as a drop in replacement for R134a in domestic refrigerators

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Cited by 63 publications
(16 citation statements)
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“…This mixture is stored as a liquid in pressurized cylinders at 0.61.2 MPa (Adolf et al, 2015). The percentage of propane and butane in LPG is different in winter and in summer, with a higher percentage of propane in winter (Price et al, 2004;El-Morsi 2015). Butane provides more energy than propane per volume by 12% when burned at temperatures above freezing.…”
Section: Literature Reviewmentioning
confidence: 99%
“…This mixture is stored as a liquid in pressurized cylinders at 0.61.2 MPa (Adolf et al, 2015). The percentage of propane and butane in LPG is different in winter and in summer, with a higher percentage of propane in winter (Price et al, 2004;El-Morsi 2015). Butane provides more energy than propane per volume by 12% when burned at temperatures above freezing.…”
Section: Literature Reviewmentioning
confidence: 99%
“…A great deal of research has been done to investigate the performance of compressor systems using hydrocarbons instead of traditional refrigerants. Energy and exergy analysis of a domestic refrigerator filled with R290, R600, and commercial LPG as an alternative to R134a was carried out by El-Morsi [2]. The results showed that the highest coefficient of performance (COP) and exergetic efficiency was obtained by R600a.…”
Section: Introductionmentioning
confidence: 99%
“…From that hypothetical investigation they reasoned that R134a, R152a, R32, HC290, HC1270, HC600 and HC600a can be utilized as an option in contrast to the above refrigerants. M El-Morsi et.al [8] performed a theoretical analysis of a VCR system using pure natural refrigerants as a substitute to HFC-134a and results revealed that LPG gives a lower COP and Isobutane gives a higher COP than that of HFC-134a by 11% and 5% respectively. M Rasti et.al.…”
Section: Introductionmentioning
confidence: 99%
“…Mass flow rate of a refrigerant (mr) is given by mr = RPM × Vsv×ρ1× ηvol/60 (8) where compressor speed is expressed as RPM, Vsv is swept volume of a compressor, refrigerant density at compressor entry can be designated as ρ1. Fig.…”
mentioning
confidence: 99%