“…This experimental observation can be qualitatively explained by considering the equilibrium isotope effect and the kinetic isotope effect affecting steps (4) and (9) in Scheme 1, by which the products CF 3 CFH 2 and CF 3 CFHD are formed. The Pd surface has a higher "affinity" towards H 2 than to D 2 because of an equilibrium isotope effect [51,52] resulting in K H 2 > K D 2 in step 4. Additionally, for step 9, the C-H (or C-D) bond formation step will be affected by a kinetic isotope effect, since the zero point energy of C-H bond is 1.1 kJ mol −1 higher than a C-D bond [53].…”