1999
DOI: 10.1021/je990199z
|View full text |Cite
|
Sign up to set email alerts
|

Empirical Correlation of Equilibrium Separation Factors in the Pd−H2/D2 System with Temperature and Composition

Abstract: The range of available data on separation factors (α) in the palladium−hydrogen/deuterium system has been extended in this study using a thermal conductivity detector. The thermal conductivity detector employed a matched pair of glass-coated bead thermistors to measure the gas-phase composition of hydrogen isotope mixtures. Separation factors (α) were measured in the β-phase, over the temperature (T) and hydrogen mole fraction (x H) ranges T = 175 K to 389 K and x H = 0.195 to 0.785, respectively. These data w… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1

Citation Types

0
1
0

Year Published

2002
2002
2016
2016

Publication Types

Select...
3

Relationship

0
3

Authors

Journals

citations
Cited by 3 publications
(1 citation statement)
references
References 10 publications
0
1
0
Order By: Relevance
“…This experimental observation can be qualitatively explained by considering the equilibrium isotope effect and the kinetic isotope effect affecting steps (4) and (9) in Scheme 1, by which the products CF 3 CFH 2 and CF 3 CFHD are formed. The Pd surface has a higher "affinity" towards H 2 than to D 2 because of an equilibrium isotope effect [51,52] resulting in K H 2 > K D 2 in step 4. Additionally, for step 9, the C-H (or C-D) bond formation step will be affected by a kinetic isotope effect, since the zero point energy of C-H bond is 1.1 kJ mol −1 higher than a C-D bond [53].…”
Section: Preferential Formation Of Cfmentioning
confidence: 99%
“…This experimental observation can be qualitatively explained by considering the equilibrium isotope effect and the kinetic isotope effect affecting steps (4) and (9) in Scheme 1, by which the products CF 3 CFH 2 and CF 3 CFHD are formed. The Pd surface has a higher "affinity" towards H 2 than to D 2 because of an equilibrium isotope effect [51,52] resulting in K H 2 > K D 2 in step 4. Additionally, for step 9, the C-H (or C-D) bond formation step will be affected by a kinetic isotope effect, since the zero point energy of C-H bond is 1.1 kJ mol −1 higher than a C-D bond [53].…”
Section: Preferential Formation Of Cfmentioning
confidence: 99%