“…(iii) In order to be able to deduce the middle case from the almost algebraic case, we require the added complication in the almost algebraic proof of working throughout with a subset E ⊆ P (G) which is a so called admissible root set for µ (see [5,Section 5]). But in our discussion of the reduced almost algebraic case in the next section we choose to work throughout with P (G) rather than with a general admissible root set for µ.…”