1972
DOI: 10.1063/1.1661126
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Electromagnetic Wave Scattering from an Active Corrugated Structure

Abstract: This paper studies the scattering of a plane wave by an active corrugated structure in which each slot region is connected to a microwave solid-state amplifier. Consequently, not only are we able to control the phase of the reflected wave but also its power gain. An exact solution to this problem has been obtained by the residue calculus method under the assumption that only the TEM wave propagates and is amplified in the slot region. Numerical results are presented for illustrating the scattering properties a… Show more

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Cited by 16 publications
(7 citation statements)
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“…The discussion so far has considered a PSS with a single active layer that can he switched between two values of surface resistance, which are related by Equation (12). A limitation of this structure is that it can only provide a single reflectivity null with a limited bandwidth.…”
Section: Reactive Single-active-layer Pssmentioning
confidence: 99%
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“…The discussion so far has considered a PSS with a single active layer that can he switched between two values of surface resistance, which are related by Equation (12). A limitation of this structure is that it can only provide a single reflectivity null with a limited bandwidth.…”
Section: Reactive Single-active-layer Pssmentioning
confidence: 99%
“…One possible way of improving RAM might be to make it active, i.e., to incorporate some means of changing the electrical parameters of its constituent materials. This might be done by using volumetric change, through materials such as controllable conducting polymer composites [9] or photo-dielectrics [IO], or by using discrete devices, such as semiconductor diodes [11][12][13][14][15]. Given that the same laws of physics will apply to both passive and active RAM, how can the latter improve on the former?…”
Section: Introductionmentioning
confidence: 99%
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“…(4) First the contribution from the incident electric field, E,'"", at the load location is found along with the similar incident field terms needed to solve (2) for a, and a,,. Then using the known values of a, and a,, the contribution from the scattered field is found from …”
Section: )mentioning
confidence: 99%