1985
DOI: 10.1016/0013-4686(95)80004-2
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Electrode kinetics of oxygen reduction on platinum in trifluoromethanesulphonic acid

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Cited by 20 publications
(18 citation statements)
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“…Figure 2 shows typical cyclic voltammograms ͑CVs͒ for the cathode at 80°C in N 2 after the injection of pure H 2 O, TFMSA, and SA for 1 h. The shape of the CV for 5 mM TFMSA was almost identical with that for pure H 2 O, due to the weak adsorption of the TFMSA anion. 9 In contrast, for 5 mM SA, additional hydrogen adsorption/ desorption peaks appeared at ca. 0.2 V, and the onset of the surface oxide formation shifted to a more positive potential.…”
Section: Resultsmentioning
confidence: 90%
“…Figure 2 shows typical cyclic voltammograms ͑CVs͒ for the cathode at 80°C in N 2 after the injection of pure H 2 O, TFMSA, and SA for 1 h. The shape of the CV for 5 mM TFMSA was almost identical with that for pure H 2 O, due to the weak adsorption of the TFMSA anion. 9 In contrast, for 5 mM SA, additional hydrogen adsorption/ desorption peaks appeared at ca. 0.2 V, and the onset of the surface oxide formation shifted to a more positive potential.…”
Section: Resultsmentioning
confidence: 90%
“…The ORR is much more complicated. And there is already a longstanding controversy on the order of the ORR on Pt. On Au, the adsorption energy of O decreases with increasing coverage according to the theoretical calculations, and this energy is the main barrier for the ORR on Au; thus, the order of ORR on Au could be higher than 1.…”
Section: Resultsmentioning
confidence: 99%
“…In CH~COOK solution, 02 is predominantly reduced through a four-electron reaction 02 + 2H20 + 4e-= 4 OH- [6] and a two electron process also occurs in K2SO4 and KC1 solutions 02+H20+2e =HO2_+OH- [7] The current ratios, x, of the four-electron and two-electron reactions for 02 reduction, calculated from the intercept in various solutions, are shown in Table I K2SO4, the H202 produced is about 8.8%. In 1M CH3COOK solution, the two-electron process is only about 1.7%, with formation of about 3.3% H202, indicating that O2 is principally reduced through a four-electron reaction.…”
Section: -mentioning
confidence: 99%