“…In Step 6, we find a unique minimum cut E −1 (C Λ ) on G ss by applying the "Reverse" Labelling Procedure of [10], where Λ is the smallest possible (Lemma 8). Figure 1(d) depicts G ss for our example, together with the following minimum cut: (2,5), (3,5), (4,6), (7,9), (8, 10)} C ins Λ = {(4, 6), (7, 9)} C copy…”