1985
DOI: 10.1016/0167-5729(85)90009-3
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Dynamical parameters of desorbing molecules

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Cited by 403 publications
(188 citation statements)
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“…The translational energy can be used to judge the collimation angle of desorption components because it is peaked at this angle in the repulsive desorption. 4,38 Each velocity distribution of desorbing N 2 clearly shows the thermalized component in the NO + CO reaction above 550 K. Typical velocity distributions at T S = 550 K and P NO = P CO =5ϫ 10 −6 Torr are shown in Fig. 7.…”
Section: Velocity Distributionmentioning
confidence: 99%
See 1 more Smart Citation
“…The translational energy can be used to judge the collimation angle of desorption components because it is peaked at this angle in the repulsive desorption. 4,38 Each velocity distribution of desorbing N 2 clearly shows the thermalized component in the NO + CO reaction above 550 K. Typical velocity distributions at T S = 550 K and P NO = P CO =5ϫ 10 −6 Torr are shown in Fig. 7.…”
Section: Velocity Distributionmentioning
confidence: 99%
“…The speed ratio is usually below unity for a hyperthermal component at around the collimation position. 38 A translational temperature of 3420 K corresponds to an energy of 0.59 eV, which is higher than the excitation energy of the molecular vibration of N 2 at the ground state, 0.28 eV. 39 Desorbing fast N 2 may involve vibrationally and/or rotationally excited molecules.…”
Section: -5mentioning
confidence: 99%
“…This dependence indicates facile energy partitionings into the rotational, vibrational, and translational modes in different ways in a repulsive product desorption event. 4,34,41,42 AR product desorption will deliver more information when it can be performed at a level of state-selective product analysis in the course of catalyzed reactions. This next stage becomes important in improving the method because each energy state of desorbing products will show different surface structures.…”
Section: Discussion and Remarksmentioning
confidence: 99%
“…Note that the expression for the angular distribution contains the factor cos ⌰ f , which ensures that a complete accommodation of parallel momentum results in a cosine distribution. 43 This factor arises from the volume element for the scattered flux per unit area on the surface at the angle ⌰ f . 24 The angular distribution for the partially conserved parallel momentum is most simply given by the integral and the ͗E f ͘ (ϭ͗E trans ͒͘/E i distribution is given by an additional factor of E trans inside the integral in the numerator.…”
Section: ͑A8͒mentioning
confidence: 99%