“…Observe that, for n = 2 with m j = 1, 1 β€ j β€ r, the graph is a complete bipartite graph K 2,r+1 , with the following vertex partition {u 0 , u 2 } and {u 1 , v j 1 ; 1 β€ j β€ r}. Thus, using [6,16], the result follows. Next to prove (ii), we assume m s = 2l + 1, where l β₯ 1.…”