1966
DOI: 10.1021/j100878a503
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Dissociation of Iridium Oxide1

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Cited by 33 publications
(10 citation statements)
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“…It is supposed to be the reduction of Ir(VI) to Ir(IV) in Eq. (4) and the transformation of unstable IrO 3 to IrO(OH) 2 [41][42][43][44][45][46][47]. M a n u s c r i p t 21 / 21…”
Section: Page 7 Of 45mentioning
confidence: 99%
“…It is supposed to be the reduction of Ir(VI) to Ir(IV) in Eq. (4) and the transformation of unstable IrO 3 to IrO(OH) 2 [41][42][43][44][45][46][47]. M a n u s c r i p t 21 / 21…”
Section: Page 7 Of 45mentioning
confidence: 99%
“…Martin (124) has also reported the following. H2RuOs(aq) = OH-(aq) + HRu04+(aq) K(20°) = 5.7 X [10][11][12][13][14][15] As a result of investigations by Silverman and Levy (187) and Connick and Hurley (45,46), we are able to give a consistent set of free energies for hydrous Ru02, Ru04-2(aq), and Ru04-(aq). Polarographic (187) and equilibrium measurements (123) in alkaline solutions have led to the following potentials.…”
Section: Thermochemistrymentioning
confidence: 99%
“…Qi.o = 1 X [10][11][12] HOs06-(aq) = H+(aq) + 0s05"2(aq) Qi.0 ^3 X [10][11][12][13][14][15][16] Free energies of HOsOs-(aq) and 0s05-2 (aq) are calculated from these values and the tabulated AG°for H20s06(aq). The principal Os(VIII) species in 1 M OHsolution is the singly charged anion, and we calculate the following potential for Os|Os(VIII) in such solutions.…”
Section: Descriptive Chemistrymentioning
confidence: 99%
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“…4~1 0~ K" and 6.2~10" K-I for Re and lr, respectively). [29] These duplex coatings are grown sequentially by CVD on a molybdenum mandrel which is subsequently removed chemically, leaving a free-standing part. [30] Typically, the Ir coating is 50-100 pm thick with a base rhenium thickness of 2500 pm.…”
Section: General Coatings For Refractory Metal Alloysmentioning
confidence: 99%