2004
DOI: 10.1007/s11253-005-0147-1
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Direct and Inverse Problems of Baire Classification of Integrals Depending on a Parameter

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Cited by 5 publications
(8 citation statements)
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“…In the case when X is a metrically quarter-stratifiable strongly countably-dimensional paracompact space or X is a metrically quarter-stratifiable space and Z is a locally convex equiconnected space (see definitions in [2]), the inclusion CC(X × X, Z) ⊆ B 1 (X 2 , Z) follows from [2, Corollary 5.2]. (4). Notice that an equiconnected space Z is locally arcwise connected.…”
Section: A Methods Of Constructing Of Separately Continuous Mappingsmentioning
confidence: 99%
See 1 more Smart Citation
“…In the case when X is a metrically quarter-stratifiable strongly countably-dimensional paracompact space or X is a metrically quarter-stratifiable space and Z is a locally convex equiconnected space (see definitions in [2]), the inclusion CC(X × X, Z) ⊆ B 1 (X 2 , Z) follows from [2, Corollary 5.2]. (4). Notice that an equiconnected space Z is locally arcwise connected.…”
Section: A Methods Of Constructing Of Separately Continuous Mappingsmentioning
confidence: 99%
“…Let X and Y be topological spaces. A mapping f : X → Y is said to be σ-continuous (see [4]), if there exists a sequence (A n ) ∞ n=1 of closed sets A n ⊆ X such that all the restrictions f | An are continuous. In [3] such functions are called piecewise continuous.…”
Section: A Methods Of Constructing Of Separately Continuous Mappingsmentioning
confidence: 99%
“…Then the map g : X → Y is continuous and g| Cn = f | Cn . Hence, condition (2) holds. Now we suppose that under conditions (a) or (b) the implication (3)⇒(1) is valid for all ordinals γ ∈ [1, α) for some α ∈ (1, ω 1 ) and prove it for α.…”
Section: Stable Baire Classes and Their Characterizationmentioning
confidence: 94%
“…Then Lemma 2.2 yields a non-empty countable set D ⊂ X such that the restriction f |D has no continuity points. Applying Lemma 2.5 (3) to the restriction f |D, we can find a countable first-countable subset Q ⊂ D without finite open sets such that f |Q is bijective and f (Q) is a discrete subspace of Y . It is clear that f |Q has no continuity point.…”
Section: Proof Of Theorem 12mentioning
confidence: 99%