1993
DOI: 10.1007/bf01560348
|View full text |Cite
|
Sign up to set email alerts
|

Dimensional regularization and the self-energy of a massive quark in a cavity

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
1
1
1

Citation Types

0
7
0

Year Published

1994
1994
2000
2000

Publication Types

Select...
4

Relationship

0
4

Authors

Journals

citations
Cited by 4 publications
(7 citation statements)
references
References 6 publications
0
7
0
Order By: Relevance
“…Secondly, there is a part which is finite for massless quarks (the free-space analogue is zero). For massive quarks, this term also diverges, and would need to be cancelled by a mass renormalization counter-term [11]. It is found that the finite part is responsible for the large O(: s ) corrections, and it seems to have the``wrong'' sign.…”
Section: Numerical Results and Discussionmentioning
confidence: 93%
See 2 more Smart Citations
“…Secondly, there is a part which is finite for massless quarks (the free-space analogue is zero). For massive quarks, this term also diverges, and would need to be cancelled by a mass renormalization counter-term [11]. It is found that the finite part is responsible for the large O(: s ) corrections, and it seems to have the``wrong'' sign.…”
Section: Numerical Results and Discussionmentioning
confidence: 93%
“…The analogous result in free-space theory is zero. For massive quarks, this term diverges, and a counter-term must be introduced into the cavity Lagrangian to renormalize the mass [11]. However, here we shall restrict our attention to massless quarks.…”
Section: Self-energy Insertsmentioning
confidence: 98%
See 1 more Smart Citation
“…bag model on a statics sphere (CQCD) [1][2][3], is a consistent relativistic quantum field theory on its own. Indeed, CQCD may be expanded perturbatively [4], and the diverging Feynman graphs have been shown to be renormalizable [5][6][7][8], e.g. in the MS scheme.…”
Section: Introductionmentioning
confidence: 99%
“…However, this good agreement has been obtained by neglecting the selfenergies of the quarks. More recently, the self-energies have been calculated, but unfortunately they turned out to be quite large [6][7][8], thus spoiling the good agreement to order α s . One has therefore argued that the self-energies should perhaps be discarded, because the boundary conditions already account for at least part of them.…”
Section: Introductionmentioning
confidence: 99%