“…An alternative presentation of .4(10,2) (see (1), p. 167) requires defining A on F(#(10,2)) to have cycle structure A = («", V 2 , V B ) (U v V t , Mg) (U 2 , V 6 , U 9 ) (U 3 , U 6 , V 9 ) (U A , U 7 , Vj) (U 5 , V 7 , V 3 ) whence A(10, 2) = </o,A>with p 10 = A 3 = ( A/9 2)2 = p 5 A p -5 A -l = I One sees that S = (pA) 2 pA-x p" 2 -When k 2 = 1 (modn), we have the graphs G(4,1), G (8, 3), G(12, 5), and #(24, 5). One verifies that <x defined on V(G(n, k)) in these four cases by = v iU is an element of A(n, k) clearly not in B(n, k).…”