2022
DOI: 10.1016/j.freeradbiomed.2021.12.303
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Detection of singlet oxygen by EPR: The instability of the nitroxyl radicals

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Cited by 15 publications
(9 citation statements)
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“…The presence of 1 O 2 was analyzed by EPR using 4-oxo-TMP to capture 1 O 2 (Figure 4D). [46] Unlike the changes caused by the presence of •OH, no significant differences were observed among the blank (H 2 O 2 ), the chitosan film and the Fe100 catalyst. This shows that if 1 O 2 was indeed present, its production was very small.…”
Section: Mechanismmentioning
confidence: 83%
“…The presence of 1 O 2 was analyzed by EPR using 4-oxo-TMP to capture 1 O 2 (Figure 4D). [46] Unlike the changes caused by the presence of •OH, no significant differences were observed among the blank (H 2 O 2 ), the chitosan film and the Fe100 catalyst. This shows that if 1 O 2 was indeed present, its production was very small.…”
Section: Mechanismmentioning
confidence: 83%
“…The principle of the detection of reactive free radical formation (ROS and carbon-centered radicals) using TEMPOL is based on monitoring the decrease in its EPR intensity ( Victória et al, 2022 ) due to the interaction of the nitroxide radical with the generated ROS species and singlet oxygen in the sample ( Victória et al, 2022 ; Matsumoto et al, 2009 ; Davies, 2016 ; Mittag et al, 2022 ). The formed species may be singlet oxygen ( 1 O 2 ), superoxide anion (O 2 − •), hydroxyl radicals (OH•) or different organic radicals (R•).…”
Section: Resultsmentioning
confidence: 99%
“…5f) has three lines (1 : 1 : 1 triplet signal) with hyperne arises from the interaction between the unpaired electron, S = 1/2, with the nuclear spin of 14 N, I = 1. 23 In view of all the above analyses, it can be concluded that the selective photooxidation of HMF to DFF in the current system is attained via different reaction pathways, including the contribution of atmospheric O 2 as well as photoinduced charge carriers.…”
mentioning
confidence: 80%
“…5f) has three lines (1 : 1 : 1 triplet signal) with hyperfine arises from the interaction between the unpaired electron, S = 1/2, with the nuclear spin of 14 N, I = 1. 23…”
mentioning
confidence: 99%