1986
DOI: 10.1007/bf01748093
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Dependence of ice nucleating ability on misfit

Abstract: RAMASAMY*Volmer developed the theory of nucleation of condensed phase on a plane foreign substrate and called it heterogeneous nucleation [1]. Laboratory and field experiments have established that AgI particles serve as effective substrates for ice nucleation. The similarity between the lattice structure of AgI and that of ice is probably a prominent factor which makes it a good catalyst [2][3][4]. The ice-nucleating ability of AgI has been found to improve when bromine atoms replace some of the iodine atoms … Show more

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Cited by 3 publications
(3 citation statements)
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“…where δ is the lattice mismatch, and a ice and a AgI are the lattice constants of ice and the silver iodide surfaces, respectively. Although previous researchers often only considered the lattice mismatch between hexagonal ice and AgI surfaces, 1,9,31,32 here we consider the lattice mismatch with both hexagonal ice and cubic ice, for reasons that will become clear below. Hexagonal ice, I h , is the stable form of ice under atmospheric conditions and cubic ice, I c , is a metastable form of ice.…”
Section: Resultsmentioning
confidence: 99%
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“…where δ is the lattice mismatch, and a ice and a AgI are the lattice constants of ice and the silver iodide surfaces, respectively. Although previous researchers often only considered the lattice mismatch between hexagonal ice and AgI surfaces, 1,9,31,32 here we consider the lattice mismatch with both hexagonal ice and cubic ice, for reasons that will become clear below. Hexagonal ice, I h , is the stable form of ice under atmospheric conditions and cubic ice, I c , is a metastable form of ice.…”
Section: Resultsmentioning
confidence: 99%
“…The lattice mismatch can be quantified with the equation where δ is the lattice mismatch, and a ice and a AgI are the lattice constants of ice and the silver iodide surfaces, respectively. Although previous researchers often only considered the lattice mismatch between hexagonal ice and AgI surfaces, ,,, here we consider the lattice mismatch with both hexagonal ice and cubic ice, for reasons that will become clear below.…”
Section: Resultsmentioning
confidence: 99%
See 1 more Smart Citation