“…Consider the matrices , ker C T = ker E T = span{( 0 1 )} for all t ∈ R. The matrices the form expected from Lemma 5.5 in[1]. The problem, as it turns out, is that ker C = ker E.Luckily, the impact of the wrong statement of [1, Lemma 5.5] on[1] is minor: all results and examples (besides Lemma 5.5, of course) remain correct, with the exception of Corollary 5.7 where it is necessary to assume the following further hypothesis:ker C(t) = ker E, ∀ t ∈ R.(A corrected statement of Corollary 5.7 of[1] can be found in the next section, Corollary 2.2. )…”