2011
DOI: 10.1080/00207160.2010.521549
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Defect correction method for time-dependent viscoelastic fluid flow

Abstract: A defect correction method for solving the time-dependent viscoelastic fluid flow, aiming at high Weissenberg numbers, is presented. In the defect step, the constitutive equation is computed with the artificially reduced Weissenberg parameter for stability, and the residual is considered in the correction step. We show the convergence of the method and derive an error estimate. Numerical experiments support the theoretical results and demonstrate the effectiveness of the method.

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Cited by 10 publications
(8 citation statements)
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“…Step 1.2. Derive the error inequalities of the momentum equation (40). From the definition of the modified Stokes projection (11)-(13), we have…”
Section: Error Estimatementioning
confidence: 99%
See 1 more Smart Citation
“…Step 1.2. Derive the error inequalities of the momentum equation (40). From the definition of the modified Stokes projection (11)-(13), we have…”
Section: Error Estimatementioning
confidence: 99%
“…. As in [38][39][40][41], to obtain an analytical solution for the considered problem, a right-hand side function is added to the momentum equation of (1). The analytical solution is…”
Section: Example 1 (Analytical Solution)mentioning
confidence: 99%
“…In this example, the theoretical convergence rates are examined by applying fluid flow across a domain Ω = [0, 1] × [0, 1] with parameters a = 0, λ = 5.0 and α = 0.5, respectively. Different authors used this experimental pattern for Stokes and Navier-Stokes equations [23,36,40,41], where the function b(x) was chosen to be the exact solution of velocity u. In this context, a right hand-side function is added to the (8) and f in (9) is studied with the help of following true solution.…”
Section: Analytical Solution Testmentioning
confidence: 99%
“…consists of Newtonian part and viscoelastic part [27]. For notational convenience, we use Einstein's convention of summation and denote differentiation with comma as ∂u ∂x i is written as u ,i and ∂u ∂t is written u t .…”
Section: Model Problemmentioning
confidence: 99%