2019
DOI: 10.1007/s00153-019-00682-x
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Deciding active structural completeness

Abstract: We prove that if an n-element algebra generates the variety V which is actively structurally complete, then the cardinality of the carrier of each subdirectly irreducible algebra in V is at most n (n+1)•n 2•n. As a consequence, with the use of known results, we show that there exist algorithms deciding whether a given finite algebra A generates the (actively) structurally complete variety V(A) in the cases when V(A) is congruence modular or V(A) is congruence meet-semidistributive or A is a semigroup.

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Cited by 2 publications
(2 citation statements)
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“…also [64]. Computational aspects of these notions are explored in [17,46,69]. 4 Evidently, a quasi-equation is passive over an algebraic quasivariety K if and only if it is passive over the variety V(K).…”
Section: Definition 71mentioning
confidence: 99%
“…also [64]. Computational aspects of these notions are explored in [17,46,69]. 4 Evidently, a quasi-equation is passive over an algebraic quasivariety K if and only if it is passive over the variety V(K).…”
Section: Definition 71mentioning
confidence: 99%
“…(A complementary demand, now called 'active structural completeness' and analysed in [17], asks that condition (iii) of Theorem 6.1 should hold for all active quasi-equations; also see [60]. Computational aspects of [active] structural completeness are addressed in [16,43,64]. )…”
Section: Passive Structural Completenessmentioning
confidence: 99%