2000
DOI: 10.1080/00927870008827115
|View full text |Cite
|
Sign up to set email alerts
|

Curves of large genus covered by the hermitian curve

Abstract: For the Hermitian curve H dened over the nite eld F q 2 , we give a complete classication of Galois coverings of H of prime degree. The corresponding quotient curves turn out to be special cases of wider families of curves F q 2 -covered by H arising from subgroups of the special linear group SL (2; F q ) or from subgroups in the normaliser of the Singer group of the projective unitary group P G U (3; F q 2 ). Since curves F q 2 -covered by H are maximal over F q 2 , our results provide some classication and e… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
1

Citation Types

0
71
0

Year Published

2001
2001
2019
2019

Publication Types

Select...
4
4

Relationship

0
8

Authors

Journals

citations
Cited by 46 publications
(71 citation statements)
references
References 25 publications
0
71
0
Order By: Relevance
“…As J.P. Serre has shown, a subcover of a maximal curve is maximal (see [10]). So one way to construct explicit maximal curves is to find equations for Galois subcovers of the Hermitian curve (see [3,7]). …”
Section: Introductionmentioning
confidence: 99%
“…As J.P. Serre has shown, a subcover of a maximal curve is maximal (see [10]). So one way to construct explicit maximal curves is to find equations for Galois subcovers of the Hermitian curve (see [3,7]). …”
Section: Introductionmentioning
confidence: 99%
“…+ y 2 + y = x q+1 . These results together with some evidence coming from [12], [13], [19] make it plausible that only few F q 2 -maximal curves can have genus close to the upper limit q(q − 1)/2. As a matter of fact, in the range…”
Section: Introductionmentioning
confidence: 84%
“…Remark 4. F q 2 -maximal curves of genus (q 2 − q + 4)/6 do exist as the following examples show, see[19],[13, Thm. 2.1]:…”
mentioning
confidence: 99%
“…The number of elements of order 3 stabilizing a fixed triangleT is 2(q 2 − q + 1), because any element in M 4 (T ) \ C q 2 −q+1 has order 3 (see [4,Section 4]).…”
Section: Proofmentioning
confidence: 99%