2011
DOI: 10.1524/ncrs.2011.0279
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Crystal structure of (E)-2-(1-methoxyimidazol-2-yl)- 2-oxoacetaldehyde O-methyl oxime, C7H9N3O3

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Cited by 2 publications
(3 citation statements)
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“…In contrast, 1-methoxy-3-methylimidazolium iodide (3) and 1,3-dimethoxyimidazolium hexafluorophosphate (4) gave complete conversion after two hours at 65 • C in either pyridine or methanol, yielding the thiones 12 and 13, respectively. 1,3-Dimethoxyimidazolium salts are known to undergo degradation in alkaline aqueous solution involving carbene formation and ring opening [49]. It is interesting enough that the desired thione was formed at all, but surprisingly no degradation occurred in methanol as judged by the absence of the tell-tale methyl NMR signals of the degradation product.…”
Section: Synthetic Considerationsmentioning
confidence: 99%
“…In contrast, 1-methoxy-3-methylimidazolium iodide (3) and 1,3-dimethoxyimidazolium hexafluorophosphate (4) gave complete conversion after two hours at 65 • C in either pyridine or methanol, yielding the thiones 12 and 13, respectively. 1,3-Dimethoxyimidazolium salts are known to undergo degradation in alkaline aqueous solution involving carbene formation and ring opening [49]. It is interesting enough that the desired thione was formed at all, but surprisingly no degradation occurred in methanol as judged by the absence of the tell-tale methyl NMR signals of the degradation product.…”
Section: Synthetic Considerationsmentioning
confidence: 99%
“…The side chain C4-C5-N3-O3-C7 adopts an almost planar conformation (deviations: C4, 0.012 Å; C5, 0.006 Å; N3, 0.018 Å; O3, 0.007 Å; C7, 0.006 Å), only the carbonyl oxygen atom O2 exhibits adistance of 0.417 Åfrom this plane. The most striking difference between the structures of the free ligand [1] and the coordinated ligand is the orientation of the side chain. In the title compound, the C4-C5 bond is rotated out of the imidazole ring plane by 50°, whereas in the free ligand it remains coplanar with the heterocyclic ring.…”
Section: Discussionmentioning
confidence: 99%
“…The nitrogen atom N3 of the side chain does not participate in any interaction which is in contrast to the situation in the free ligand [1]. Theimidazole ringsare orientedinaparallel manner,stacked in the direction of the crystallographic b axis, with an interplanar distance of 8.14 Å. Symmetry codes i: 1+x,y,z;ii: -1-x,1-y,-z.…”
Section: Discussionmentioning
confidence: 99%