1982
DOI: 10.1002/crat.2170170703
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Crystal Growth in Magnetic Fields (II) Crystallization of Co(NH4)2(SO4)2 · 6 H2O from Aqueous Solutions in High Magnetic Fields

Abstract: Crystal Growth in Magnetic Fields (11)Crystallization of CO(NH&(SO~)~ . 6 HzO from Aqueous Solutions in High Magnetic FieldsThe displacement rate of (110) single crystal faces of Co(NH,),(SO,), 6 H,O has been measured in dependence on the supersaturation of aqueous solutions in the zero field and at magnetic flux densities of 7 T. The results show that in a given external field measurable effects near the equilibrium don't occur (thermostatic field effect). On the contrary a marked influence at extreme relativ… Show more

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Cited by 10 publications
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“…To determine whether the thermodynamic effect of the applied magnetic field can contribute to the increase of growth rates of the observed crystals, the temperature shift ΔT (the corresponding isothermal change of supersaturation) was estimated. The proposed formula was used, 3 =…”
Section: ■ Discussionmentioning
confidence: 99%
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“…To determine whether the thermodynamic effect of the applied magnetic field can contribute to the increase of growth rates of the observed crystals, the temperature shift ΔT (the corresponding isothermal change of supersaturation) was estimated. The proposed formula was used, 3 =…”
Section: ■ Discussionmentioning
confidence: 99%
“…To determine whether the thermodynamic effect of the applied magnetic field can contribute to the increase of growth rates of the observed crystals, the temperature shift Δ T (the corresponding isothermal change of supersaturation) was estimated. The proposed formula was used, normalΔ T = H 2 T 2 normalΔ 0 H μ 0 χ , where H is the strength of the magnetic field, T is the growth temperature, Δ 0 H is the molar enthalpy of crystallization, μ 0 is the magnetic permeability of the vacuum, and χ is the molar magnetic susceptibility of the solution. The estimated value of the temperature shift of the crystallization temperature caused by the magnetic field is Δ T ≈ 4.2 × 10 –4 .…”
Section: Discussionmentioning
confidence: 99%
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