2009
DOI: 10.1016/j.ijheatmasstransfer.2009.08.013
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Critical times in multilayer diffusion. Part 1: Exact solutions

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Cited by 74 publications
(50 citation statements)
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“…Thus, considering a 10‐m thick uncontaminated clay or shale unit with a diffusion coefficient D = 10 −10 m 2 /s, we could calculate how long it takes for solute contaminants accumulating at the top surface of the unit to diffuse across this 10‐m thick clay aquitard and come to a new equilibrium. Although there are multiple definitions of response time, or critical time, because mathematically an infinite amount of time is required for diffusive processes to reach steady state (Landman and McGuinness 2000; Hickson et al 2009), a common approximation of critical time is found using the exact solution of for a single layer of material with boundary conditions of solute concentration, C = C 0 (a constant) at the upper surface of the layer, and C = 0 at the lower surface, and initial concentration of the contaminant solute of zero everywhere (Crank 1975, 51–52) as which corresponds to approximately 84% of the average steady‐state concentration at equilibrium (Hickson et al 2009). Based on , it will take more than 5000 years for the solutes to diffuse across that aquitard, demonstrating the exceedingly large response times of systems dominated by chemical diffusion.…”
Section: Understanding Flow and Transport Problems Through Scaling Anmentioning
confidence: 99%
See 1 more Smart Citation
“…Thus, considering a 10‐m thick uncontaminated clay or shale unit with a diffusion coefficient D = 10 −10 m 2 /s, we could calculate how long it takes for solute contaminants accumulating at the top surface of the unit to diffuse across this 10‐m thick clay aquitard and come to a new equilibrium. Although there are multiple definitions of response time, or critical time, because mathematically an infinite amount of time is required for diffusive processes to reach steady state (Landman and McGuinness 2000; Hickson et al 2009), a common approximation of critical time is found using the exact solution of for a single layer of material with boundary conditions of solute concentration, C = C 0 (a constant) at the upper surface of the layer, and C = 0 at the lower surface, and initial concentration of the contaminant solute of zero everywhere (Crank 1975, 51–52) as which corresponds to approximately 84% of the average steady‐state concentration at equilibrium (Hickson et al 2009). Based on , it will take more than 5000 years for the solutes to diffuse across that aquitard, demonstrating the exceedingly large response times of systems dominated by chemical diffusion.…”
Section: Understanding Flow and Transport Problems Through Scaling Anmentioning
confidence: 99%
“…which corresponds to approximately 84% of the average steady-state concentration at equilibrium (Hickson et al 2009). Based on Equation 6, it will take more than 5000 years for the solutes to diffuse across that aquitard, demonstrating the exceedingly large response times of systems dominated by chemical diffusion.…”
Section: R E T R a C T E Dmentioning
confidence: 99%
“…To determine whether it is appropriate to work with such steady state solutions, we must decide whether a sufficient amount of time has passed so that the transient solution has effectively reached steady state. Several definitions of critical time have been proposed for this purpose [1][2][3][4][5][6][7]. One such definition, the mean action time (MAT) [3][4][5][6][7][8], also known as the local accumulation time [9][10][11][12], is the mean of a probability density function (PDF) associated with the linear reaction-diffusion problem of interest.…”
Section: Introductionmentioning
confidence: 99%
“…with T and F defined in Eqs. (20), (22), respectively, in which λ is replaced by s. To obtain the propagator in time domain, one needs to perform an inverse Laplace transform. This is done by looking for the poles s = λ n ofG and the above formula shows that they are given by the zeros of F (s), as expected.…”
Section: Computation Of the Normmentioning
confidence: 99%