2010
DOI: 10.1016/j.physa.2009.11.006
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Critical exponents for Fréedericskz transition in nematics between concentric cylinders

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Cited by 11 publications
(1 citation statement)
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“…No generality is lost by assuming that U>0 for t(0,logρ) and thus that U achieves its maximum value, A say, at t=(logρ)/2. Then may be integrated twice to yield the implicit solution 0U(t;δ)1δcos2uδcos2uδcos2Adu=tfor 0<t<(logρ)/2, where the amplitude A is related to ρ and δ by 0A1δcos2uδcos2uδcos2Adu=logρ2.An analogous solution was obtained in to describe the Fréedricksz transition in an annulus with strong perpendicular anchoring. For the special limiting case δ=1, we can solve exactly to find Ufalse(1;tfalse)=prefixcos1ρetρ+1+normaletρ+1,with associated amplitude A=prefixcos12ρ1+ρ.…”
Section: The Defect‐free State In Of Theorymentioning
confidence: 99%
“…No generality is lost by assuming that U>0 for t(0,logρ) and thus that U achieves its maximum value, A say, at t=(logρ)/2. Then may be integrated twice to yield the implicit solution 0U(t;δ)1δcos2uδcos2uδcos2Adu=tfor 0<t<(logρ)/2, where the amplitude A is related to ρ and δ by 0A1δcos2uδcos2uδcos2Adu=logρ2.An analogous solution was obtained in to describe the Fréedricksz transition in an annulus with strong perpendicular anchoring. For the special limiting case δ=1, we can solve exactly to find Ufalse(1;tfalse)=prefixcos1ρetρ+1+normaletρ+1,with associated amplitude A=prefixcos12ρ1+ρ.…”
Section: The Defect‐free State In Of Theorymentioning
confidence: 99%