2004
DOI: 10.1007/978-3-540-30502-6_1
|View full text |Cite
|
Sign up to set email alerts
|

Counting by Coin Tossings

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

0
12
0
1

Year Published

2006
2006
2023
2023

Publication Types

Select...
4
3
2

Relationship

1
8

Authors

Journals

citations
Cited by 20 publications
(13 citation statements)
references
References 20 publications
0
12
0
1
Order By: Relevance
“…The problem of counting items in a large datastream inspires several classes of algorithms, including approximate counting, probabilistic counting, sampling, and sketches; see "Counting by Coin Tossings" [7] for a survey. Approximate counting is beneficial by itself, and lately it has been combined with the other classes.…”
Section: Approximate Counting In Streamsmentioning
confidence: 99%
“…The problem of counting items in a large datastream inspires several classes of algorithms, including approximate counting, probabilistic counting, sampling, and sketches; see "Counting by Coin Tossings" [7] for a survey. Approximate counting is beneficial by itself, and lately it has been combined with the other classes.…”
Section: Approximate Counting In Streamsmentioning
confidence: 99%
“…Exponential functionals of Poisson process and, more generally, of Lévy processes, appear in a number of important applications. For instance, they are relevant to the analysis of randomized algorithms (F lajolet , 2004) and in mathematical finance (B ertoin and Y or , 2005). In D umas et al.…”
Section: Related Research Areasmentioning
confidence: 99%
“…The relative standard deviation of the estimaten is shown in [10] to be very nearly independent of n. Kruskal and Greenberg presented an adaptable approach to approximate counting based on the Morris algorithm in their work [8]. A review of probabilistic counting algorithms for data streaming applications can be found in [4].…”
Section: Background and Related Workmentioning
confidence: 99%
“…We pause at this point to recall that if fn satisfies the recursion of the type fn+1 = gn + fn (4) for n ≥ k, then a closed form expression for fn valid for all n ≥ k + 1 can be obtained via (3) is of type (4). Assuming that the counter starts at x0 = const, the initial condition of (3) is y0 = f (x0) = const (that is, for k = 0), and the solution is…”
Section: Algorithm Descriptionmentioning
confidence: 99%