1999
DOI: 10.1023/a:1022475520126
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Countable Products of Čech-scattered supercomplete spaces

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Cited by 3 publications
(9 citation statements)
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References 31 publications
(30 reference statements)
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“…The proof is very similar to the one given in [20] for the case of countably manyČech-scattered paracompacta. Therefore, we will only give the main steps of the proof and refer the reader to [20] for details. Let G be an open cover of ΠX i .…”
Section: Countable Products Of σ-Partition-complete Supercomplete Spasupporting
confidence: 64%
See 2 more Smart Citations
“…The proof is very similar to the one given in [20] for the case of countably manyČech-scattered paracompacta. Therefore, we will only give the main steps of the proof and refer the reader to [20] for details. Let G be an open cover of ΠX i .…”
Section: Countable Products Of σ-Partition-complete Supercomplete Spasupporting
confidence: 64%
“…As in [19], [20], we may extend the proof of 6.1 to the σ-partition-complete case. (Recall that a space is called σ-partition-complete if it is a countable union of partition-complete, closed subspaces.)…”
Section: Countable Products Of σ-Partition-complete Supercomplete Spamentioning
confidence: 99%
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“…As an excellent result, Friedler et al [5], Hohti and Pelant [7] showed that if {X n : n ∈ ω} is a countable collection of C-scattered paracompact spaces, then the product ∏ n∈ω X n is paracompact. As a generalization of C-scattered spaces,Čech-scattered spaces introduced by Hohti and Ziqiu [8] play the same fundamental role in the study of paracompactness of countable products. In 2005, Aoki and Tanaka [1] extended the Hohti and Ziqiu's results by proving that if Y is a perfect paracompact space, and {X n : n ∈ ω} is a countable collection ofČech-scattered paracompact spaces, then the product Y × ∏ n∈ω X n is paracompact.…”
Section: Introductionmentioning
confidence: 99%
“…Remark 3.6. If {X n : n ∈ ω} is a countable collection ofČech-scattered screenable spaces, we can assume that X n =X for each n ∈ ω, and X is topped with Top(X)={a} for some a ∈ X, see [1,8]. Therefore, by Theorem 3.4, the product ∏ n∈ω X n is screenable.…”
mentioning
confidence: 99%