1996
DOI: 10.1006/jabr.1996.0035
|View full text |Cite
|
Sign up to set email alerts
|

Conjugacy Separability of Amalgamated Free Products of Groups

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

0
43
0

Year Published

1996
1996
2017
2017

Publication Types

Select...
5
3

Relationship

0
8

Authors

Journals

citations
Cited by 36 publications
(43 citation statements)
references
References 21 publications
0
43
0
Order By: Relevance
“…Let p be the epimorphism from π 1 (M) to π 1 (O). Since π 1 (O) is virtually free, the intersection of p(C 1 ) and p(C 2 ) is trivial since the intersection of p(C 1 ) ∩ p(C 2 ) is (see Lemma 3.6 in [24]), so the intersection of C 1 and C 2 is Z.…”
Section: Proofmentioning
confidence: 99%
“…Let p be the epimorphism from π 1 (M) to π 1 (O). Since π 1 (O) is virtually free, the intersection of p(C 1 ) and p(C 2 ) is trivial since the intersection of p(C 1 ) ∩ p(C 2 ) is (see Lemma 3.6 in [24]), so the intersection of C 1 and C 2 is Z.…”
Section: Proofmentioning
confidence: 99%
“…Then, by [7,Lemma 2.8], the element b also stabilizes a vertex of S(G). This means that a and b are conjugate in G with some elements of G1 or G2.…”
Section: Case 1 the Element A Stabilizes A Vertex Of The Graph S(g)mentioning
confidence: 93%
“…Let G = Gx *H G2 be the amalgamated free product of groups G1 and G2 by the subgroup H. Dyer [6] showed that if both Ga and G2 are free or both are finitely generated nilpotent groups and if H is cyclic, then G = Ga *H G2 is finitely approximable with respect to conjugacy. Recently Ribes and Zalesskii [7] generalized this result to the case in which Ga and G~ are almost free or almost finitely generated nilpotent groups (not necessarily of the same type) and H is cyclic.…”
mentioning
confidence: 90%
“…Observe that the profinite completion N of Π has exactly the same presentation and so N F 1 * F 2 is a profinite amalgamated free product of two finitely generated free profinite groups with a procyclic amalgamated subgroup. In fact, this profinite amalgamated free product is proper (see [11,Proposition 3.2]) in the sense that F 1 , Z and F 2 are naturally embedded in N .…”
Section: There Is An Open Normal Subgroupmentioning
confidence: 99%